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分布式系统框架(V2.0) 轻松承载百亿数据,千万流量!讨论专区 - 源码下载 - 官方教程

HttpHelper爬虫框架(V2.7-含.netcore) HttpHelper官方出品,爬虫框架讨论区 - 源码下载 - 在线测试和代码生成

HttpHelper爬虫类(V2.0) 开源的爬虫类,支持多种模式和属性 源码 - 代码生成器 - 讨论区 - 教程- 例子

查看: 6580|回复: 3

[HttpHelper] 网址无法抓取

[复制链接]
发表于 2017-3-3 16:48:20 | 显示全部楼层 |阅读模式
url:http://www.cp46.com/videoapi/pk1 ... er=GetPk10AwardData
可以用浏览器打开 但是用爬虫类打不开...



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发表于 2017-3-3 17:38:07 | 显示全部楼层
[HTML] 纯文本查看 复制代码
<html><body><script language="javascript"> window.onload=setTimeout("gp(184)", 200); function gp(VF) {var qo, mo="", no="", oo = [0x51,0x66,0xb1,0xe7,0x2c,0x68,0x8f,0xc3,0xfe,0x42,0xbb,0xf1,0x4a,0x84,0xbe,0xfc,0x3b,0x6f,0x9c,0x27,0x99,0xc3,0x14,0x47,0x67,0x9d,0xda,0x0d,0x45,0x8c,0xe8,0x1f,0x5a,0x90,0xc4,0x4f,0x14,0x9c,0xd0,0x52,0xd6,0x0c,0x5b,0xe4,0x6c,0xee,0x22,0xb2,0x92,0xc6,0x56,0x89,0x12,0x43,0x5c,0x92,0x1a,0x52,0xda,0x5b,0x1d,0x50,0xd4,0x5a,0x8b,0x08,0x46,0xc9,0x02,0x38,0xbb,0x38,0xfd,0x81,0x03,0x86,0xb9,0x36,0xc7,0x57,0xdb,0x0f,0x96,0x11,0x1c,0x4f,0xd2,0x55,0xda,0x0d,0x6c,0xa0,0x23,0xab,0x33,0x69,0x0c,0x3f,0xcf,0x4c,0xd4,0x58,0x7c,0x0c,0x9b,0x20,0xa3,0x2c,0x34,0xbb,0x40,0xc2,0x4f,0xc8,0x0d,0x41,0x92,0xd9,0x1a,0x5f,0x32,0x66,0xac,0x37,0x4a,0x8f,0xbc,0xfc,0x78,0xef,0x77,0xfd,0x3a,0xb6,0xd2,0x09,0x50,0xcc,0x9c,0x23,0xa5,0x1d,0xa5,0x2e,0x73,0x01,0x87,0x0a,0x97,0x1e,0x5f,0xe1,0x59,0x6b,0x87,0xac,0x96,0x23,0x9c,0xcf,0x0a,0x46,0x35,0x6d,0xad,0xe8,0x73,0xee,0xe1,0x18,0x5f,0xe4,0x66,0xdf,0xe7,0x1e,0x58,0x94,0x21,0x9a,0x71,0xba,0xf2,0x36,0x75,0x02,0x29,0xa3,0x16,0xa4,0x1c,0x5e,0x08,0x48,0x81,0xb6,0xf0,0x31,0xf9,0x73,0xa8,0xe2,0x17,0x5b,0xd9,0x16,0x4a,0x83,0xc8,0x42,0x69,0xa6,0xe0,0x15,0x4d,0x92,0xdb,0x1c,0x56,0x8f,0x1c,0x4f,0x4c,0x86,0xbc,0x00,0x3b,0x6f,0x0d,0x48,0x8b,0x05,0x29,0x50,0xad,0x8f,0x3b];qo = "qo=235; do{oo[qo]=(-oo[qo])&0xff; oo[qo]=(((oo[qo]>>1)|((oo[qo]<<7)&0xff))-196)&0xff;} while(--qo>=2);"; eval(qo);qo = 234; do { oo[qo] = (oo[qo] - oo[qo - 1]) & 0xff; } while (-- qo >= 3 );qo = 1; for (;;) { if (qo > 234) break; oo[qo] = ((((((oo[qo] + 140) & 0xff) + 124) & 0xff) << 1) & 0xff) | (((((oo[qo] + 140) & 0xff) + 124) & 0xff) >> 7); qo++;}po = ""; for (qo = 1; qo < oo.length - 1; qo++) if (qo % 6) po += String.fromCharCode(oo[qo] ^ VF);eval("qo=eval;qo(po);");} </script> </body></html>


可以啊,这不是能取到吗?
发表于 2017-3-3 22:04:45 | 显示全部楼层
第一次访问,返回js,js的内容就是cookie,第二次访问,带着第一次的cookie,就有东西返回了。
 楼主| 发表于 2017-3-4 07:12:13 | 显示全部楼层
我看下,,,谢谢~
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